Overview
Process cooling can be an expensive. In general, we
use the following guidelines when trying to reduce cooling costs.
1. Eliminate
"once-through" cooling.
2. Use cooling towers rather
than chillers when feasible.
3. Apply for sewer exemption on
cooling tower make-up water.
4. Use gas-powered chillers
rather than electric chillers when cost-effective.
Tower Performance
A cooling tower is a counter-flow or cross-flow heat
exchanger that removes heat from water and transfers it to air. Cooling towers come in many
configurations. Induced-draft cooling
towers, such as the one shown below, generally use less fan power and have
short circuit less air than forced-draft cooling towers.
Figure 1.
Induced-draft cross-flow cooling tower (Source: ASHRAE Handbook: HVAC
Systems and Equipment, 2000)
The temperature difference of water through a tower, dT =
Tw1-Tw2, is determined by the load, Ql, and the mass flow rate of water,
mw. Neither the size of the tower nor
the state of the outside air influences the temperature difference; however,
larger towers or lower outdoor air wet-bulb temperatures will decrease the exit
water temperature, Tw2.
Typically, most towers are sized for a 10 F temperature
difference and about 2.4 gpm/ton of cooling.
Fan motor hp is about 0.1 hp/ton and air flow rates are about 2,000
cfm/hp. The temperature of water from a cooling tower, Tw2, can be calculated
based on tower performance data such as that shown below, water flow rate,
cooling load, and the ambient wet-bulb temperature. This process can be automated in software to
predict cooling tower performance with varying ambient conditions. For example, CoolSim (Kissock, 1997)
calculates exit water temperatures, and the fraction of time that a cooling
tower can deliver water at a target temperature, based on entering water
temperature, Tw1, and TMY2 weather data.
This information is useful in determining how often a cooling tower can
replace a chiller in cooling applications.
Figure 2. Typical
cooling tower performance curve (Source: ASHRAE Handbook: HVAC Systems and
Equipment, 2000).
Sensible and
Latent Cooling
Depending on the entering air and water temperatures, the
water may be cooled by sensible and latent cooling of the air, or simply by
latent cooling of the air. In either
case, latent, i.e. evaporative, cooling is dominant. For example, consider the case in which the
air enters at a lower temperature than the water (Figure 3a). The air will leave completely saturated and
the cooling is part sensible and part latent.
The sensible portion occurs as the air temperature increases by
absorbing heat from the water. The
latent portion occurs as some of the water evaporates, which draws energy out
of the water.
If the air enters at the same wet bulb temperature as
before, but at a higher dry-bulb temperature than the water, then the air will
cool as it saturates (Figure 3b). Thus,
the sensible cooling component is negative, and the all the cooling is due to
evaporation. In general, cooling is dominated by latent cooling.
Figure 3.
Psychrometric process lines for air through a cooling tower, if the
entering air temperature is a) less than the entering water temperature,
and b) greater than the entering water temperature.
The total cooling, ma (ha2 – ha1) is the same for both
cases since enthalpy is a function of wet-bulb temperature alone. However, the dry-bulb temperature
significantly influences the evaporation rate, mwe = ma (wa2-wa1). The rate of evaporation increases as the
dry-bulb temperature increases for a given wet-bulb temperature.
Evaporation Rate
As discussed in the previous section, cooling in cooling
towers is dominated by evaporation. The
evaporation rate can be calculated from the pyschrometric relations in the
previous section, if the inlet and exit conditions of the air are known. For example, consider the case in which the
cooling load, Ql, mass flow rate of air, ma, (which can be calculated based on
the fan cfm and specific volume of the inlet air), and inlet conditions of air
are known. The enthalpy of the exit air,
ha2, can be calculated from an energy balance.
Ql = ma (ha2 – ha1)
ha2 = ha1+ Ql / ma
The state of the exit air can be fixed by assuming that it
is 100% saturated with an enthalpy ha2. The evaporation rate, mwe, can be determined
by a water mass balance on the air.
mwe = ma (wa2- wa1)
The fraction of water evaporated is:
mwe / mw
Using this method for entering air temperatures from 50 F
to 90 F, we determined that the fraction of water evaporated typically ranges
from about 0.5% to 1%, with an average value of about 0.75%.
Another way to estimate the fraction of water evaporated
is to assume that all cooling, Ql, is from evaporation, Qevap. The cooling load Ql, is the product of the
water flow rate, mw, specific heat, cp, and temperature difference, dT. The evaporative cooling rate is the product
of the water evaporated, mwe, and the latent heat of cooling, hfg.
Ql = Qevap
mw cp dT = mwe hfg
Assuming the latent heat of evaporation of water, hfg, is
1,000 Btu/lb, and the temperature difference of water through the tower, dT, is
10 F, the fraction of water evaporated is:
mwe / mw = cp dT / hfg = 1 (Btu/lb-F) x 10 (F) / 1000
(Btu/lb) = 1%
If on average, 75% of the cooling were from evaporation
and 25% from sensible cooling, then the evaporation rate would be:
75% x 1% = 0.75%
Thus, both methods suggest that 0.75% is a good estimate
of for the rate of evaporation; however, we have seen manufacturer data
indicating average evaporation rates as low as 0.30%. Water lost to evaporation should not be
subjected to sewer charges. Typical
sewer charges are about $2.20 per hundred cubic feet.
Some water may be lost as water droplets are blown from
the tower by oversized fans or wind. This
type of water loss is called “drift”.
Drift rates are typically about 0.2% of flow (ASHRAE Handbook, HVAC
Systems and Equipment, 2000); however, we generally assume that drift losses
are included in the 0.75% evaporation rate.
Water Treatment and Blow Down Rate
Cooling tower water must be treated to prevent bacterial
growth and maintain the concentration of dissolved solids at acceptable levels
to prevent scale and corrosion.
Bacterial Growth
The typical method of controlling bacterial growth is to
add biocides at prescribed intervals and to keep the cooling tower water
circulating. If the tower will not be
operated for a sustained period of time, then the cooling water should be
drained.
Dissolved Solids
Water evaporated from a cooling tower does not contain
dissolved solids. Thus, the
concentration of dissolved solids will increase over time if only enough water
is added to the tower to compensate for evaporation. To maintain the dissolved solids at
acceptable levels, most towers periodically discharge some water and replace it
with fresh water. This process is called
blow down. It the level of dissolve
solids increases too high, scale will be begin to form, and/or the water may
become corrosive and damage piping, pumps, cooling tower surfaces and heat
exchangers. Usually, the primary
dissolved solid to control is calcium carbonate CaCO3.
Blow down can be accomplished by continuously adding and
removing a small quantity of water, periodically draining and refilling the
cooling tower reservoir, or by metering the conductivity of water and adding
fresh water only when needed. By far the
most efficient method is to meter the conductivity of water, which increases in
proportion to the level of dissolved solids, and add fresh water only when needed.
The required quantity of blow down water depends on the
acceptable quantity of dissolved solids in the tower water, PPMtarget, the
quantity of dissolved solids in the makeup water, PPMmu, and the evaporation
rate, mwe. The target level of dissolved
solids is typically quantified in cycles, where:
Cycles = PPMtarget / PPMmu
For example, if the quantity of dissolved CaCO3
in the makeup water, PPMmu, is 77 ppm and the maximum level to prevent scaling,
PPMtarget, is 231, then the cooling tower water must be maintained at three
cycles:
Cycles = PPMtarget / PPMmu = 231 ppm / 77 ppm = 3
By applying mass balances, it can be shown that the blow
down water required to maintain a certain number of cycles is
mwbd = mwe / (Cycles –1)
The total makeup water required mwmu, is the sum of the
water added for evaporation and blow down:
mwmu = mwe + mwbd
For example for a 1,000 gpm tower with a 0.75% evaporation
rate and CaCO3 concentration at 3 Cycles, the quantity of makeup
water required would be about:
mwe = (mwe/mw) x mw = 0.75% x 1,000 gpm = 7.5 gpm
mwbd = mwe / (Cycles –1) = 7.5 gpm / (3 – 1) = 3.75 gpm
mwmu = mwe + mwbd = 7.5 gpm + 3.75 gpm = 11.25 gpm
No comments:
Post a Comment